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Stephen_C's avatar
Stephen_C
Icon for Neophyte rankNeophyte
12 months ago
Solved

Report/dashboard which contains groups that do not contain a specific resource?

It is possible to create a report/dashboard that contains groups that do not contain a specific resource?

For example, I need to find all groups that do not contain resources starting with sw0.

  • Anonymous's avatar
    Anonymous
    12 months ago

    It's not a regex match (i originally was going to, but decided against it). Look at line 9. That takes care of making sure it starts with sw0.

    By intense, i mean long running. It has to make an API call for every group. You won't run into any limits though because the endpoint path is different for every call, so different rate limit buckets. You'd probably be fine running this once a day (and switching to CSV output).

    Pagination added:

    # Get groups without a certain device in them
# warning this does not use pagination, may have incomplete results if you have more than 1000 groups or more than 1000 devices in a group.
from lm import lm
pattern = "sw0"
groups_without_target_device = []
groups = []
end_found = False
offset = 0
size = 1000
while not end_found:
    current = lm.get_device_group_list(size=size,offset=offset).items
    groups += current
    offset += len(current)
    end_found = len(current) != size
for id,group_details in {x.id:x for x in groups}.items():
    members = []
    end_found = False
    offset = 0
    size = 1000
    while not end_found:
        current = lm.get_immediate_device_list_by_device_group_id(id, size=size,offset=offset).items
        members += current
        offset += len(current)
        end_found = len(current) != size
    matching_count = len([x for x in members if x.display_name.startswith(pattern)])
    full_path = '\\' if group_details.full_path == '' else group_details.full_path
    print(f"Group \"{full_path}\" contains {matching_count} devices starting with {pattern}")

     

  • Anonymous's avatar
    Anonymous
    12 months ago

    Ah, i can't edit. line four needs to be:

    pattern = "sw0"

     

    • Stephen_C's avatar
      Stephen_C
      Icon for Neophyte rankNeophyte
      12 months ago

      Thanks Stuart. Unfortunately, there are definately more than 1000 groups, but nore more than 1000 devices per group. I think the pattern would need to be set as below though seeing as I am looking for devices starting with that.

      pattern = "^sw0"

      How intense do you think this would be though? We have a number of scripts doing API calls pretty frequently. If I can have this output to CSV once a day it would probably be sufficient...

      • Anonymous's avatar
        Anonymous
        12 months ago

        It's not a regex match (i originally was going to, but decided against it). Look at line 9. That takes care of making sure it starts with sw0.

        By intense, i mean long running. It has to make an API call for every group. You won't run into any limits though because the endpoint path is different for every call, so different rate limit buckets. You'd probably be fine running this once a day (and switching to CSV output).

        Pagination added:

        # Get groups without a certain device in them
# warning this does not use pagination, may have incomplete results if you have more than 1000 groups or more than 1000 devices in a group.
from lm import lm
pattern = "sw0"
groups_without_target_device = []
groups = []
end_found = False
offset = 0
size = 1000
while not end_found:
    current = lm.get_device_group_list(size=size,offset=offset).items
    groups += current
    offset += len(current)
    end_found = len(current) != size
for id,group_details in {x.id:x for x in groups}.items():
    members = []
    end_found = False
    offset = 0
    size = 1000
    while not end_found:
        current = lm.get_immediate_device_list_by_device_group_id(id, size=size,offset=offset).items
        members += current
        offset += len(current)
        end_found = len(current) != size
    matching_count = len([x for x in members if x.display_name.startswith(pattern)])
    full_path = '\\' if group_details.full_path == '' else group_details.full_path
    print(f"Group \"{full_path}\" contains {matching_count} devices starting with {pattern}")

         

  • Anonymous's avatar
    Anonymous
    12 months ago

    I can't think of a way to do this without resorting to the API/SDK. Would likely be pretty intense because you'd need to grab every group ID then grab the members of each group. This should work:

    # Get groups without a certain device in them
# warning this does not use pagination, may have incomplete results if you have more than 1000 groups or more than 1000 devices in a group.
from lm import lm
pattern = "sw0.*"
groups_without_target_device = []
groups = lm.get_device_group_list(size=1000,fields="id,name,fullPath").items
for id,group_details in {x.id:x for x in groups}.items():
    members = lm.get_immediate_device_list_by_device_group_id(id, size=1000).items
    matching_count = len([x for x in members if x.display_name.startswith(pattern)])
    full_path = '\\' if group_details.full_path == '' else group_details.full_path
    print(f"Group \"{full_path}\" contains {matching_count} devices starting with {pattern}")

    Uses my lmwrapper which relies on the sdk.